If it takes 4.00 J of work to stretch a Hooke's Law spring 10.0 cm from its unstressed length, determine the extra work required to stretch it an additional 10.0 cm

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so the question asks to determine the extra work to stretch the string from 10 to 20 cm, so it's obvious that the extra amount of work is greater than the first work done, so we can do cross product when w1=4, x1=0.1m and when w2-4(which is w2-w1), x=0.2 so we'll get x2-4=(4*0.2)/ 0.1, we'll get 8, and then we'll get -4 to the other side wich will give us 8+4=12 and that's your ansewr.

That's my method and i'm not sure if it could work in other examples, hope it makes sense
joe mommma
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