Asked by Luke

If it takes 4.12 J of work to stretch a Hooke's law spring 12.1 cm from its unstressed length, determine the extra work required to stretch it an additional 10.0 cm.
Answered by MathMate
The stress-strain curve for a Hooke's law spring is a triangle. The area is the work done. Therefore the work done is proportional to the square of the displacement from unstressed state.
4.12 J : 12.1²
X : (12.1+10)²
Can you take it from here?
Answered by H
No
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