It takes 5.28 J of work to stretch a Hookes Laq spring 9.82 cm from its unstressed length. How much extra work is required to stretch an additional 11.9 cm? anwser in J
Figure the Potential energy at 11.9, and at 9.82cm. The difference is the energy that stretched the spring.
Or, the calculus way..
Work= INT kxdx from .0982 to .119 m
i have nooooooooo clue sowwie