It takes 1 molecule of nitrogen and 3

Question

molecules of hydrogen to produce 2
molecules of ammonia using the following formula:

1N2+ 3H2 → 2NH3

Identify which combination of molecules will produce ammonia with no leftovers?

(1 point)
Responses

5N2 and 6H2
5 n sub 2 and 6 h sub 2

2N2 and 6H2
2 n sub 2 and 6 h sub 2

8N2 and 4H2
8 n sub 2 and 4 h sub 2

4N2 and 4H2

Answer 1

To determine which combination of molecules will produce ammonia with no leftovers, we can analyze the stoichiometry of the reaction:

The reaction is: \[ 1N_2 + 3H_2 \rightarrow 2NH_3 \]

From this equation, we can see that:

• 1 molecule of \(N_2\) reacts with 3 molecules of \(H_2\) to produce 2 molecules of \(NH_3\).

Now, let's evaluate each option:

1. 5N2 and 6H2:

   • For 5 molecules of \(N_2\), you would need \(5 \times 3 = 15\) molecules of \(H_2\).
   • This combination will produce ammonia, but it has leftover \(H_2\) (15 needed, 6 provided).

2. 2N2 and 6H2:

   • For 2 molecules of \(N_2\), you would need \(2 \times 3 = 6\) molecules of \(H_2\).
   • This combination will produce \(2 \times 2 = 4\) molecules of \(NH_3\) and uses both \(N_2\) and \(H_2\) with no leftovers.

3. 8N2 and 4H2:

   • For 8 molecules of \(N_2\), you would need \(8 \times 3 = 24\) molecules of \(H_2\).
   • This combination will produce ammonia, but it has leftover \(N_2\) (24 needed, 4 provided).

4. 4N2 and 4H2:

   • For 4 molecules of \(N_2\), you would need \(4 \times 3 = 12\) molecules of \(H_2\).
   • This combination will produce ammonia, but it has leftover \(H_2\) (12 needed, 4 provided).

Based on this analysis, the correct answer is:

2N2 and 6H2.

This combination produces ammonia with no leftovers.