Question

It takes 1 molecule of nitrogen and 3 molecules of hydrogen to produce 2 molecules of ammonia using the following formula:1N2+ 3H2 → 2NH3 Identify which combination of molecules will produce ammonia with no leftovers?(1 point)Responses4N2 and 4H24 n sub 2 and 4 h sub 22N2 and 6H22 n sub 2 and 6 h sub 28N2 and 4H28 n sub 2 and 4 h sub 25N2 and 6H25 n sub 2 and 6 h sub 2

Answer 1

To produce ammonia (NH₃) using the reaction \( 1N_2 + 3H_2 \rightarrow 2NH_3 \), we need to determine which combination of molecules will use all reactants with none left over.

The stoichiometry of the reaction indicates:

• 1 molecule of N₂ produces 2 molecules of NH₃.
• 3 molecules of H₂ are needed for the same reaction.

From the equation, we can deduce:

• For every 1 N₂, we need 3 H₂.
• Therefore, to produce ammonia without leftovers, the ratio of N₂ to H₂ must always be maintained at 1:3.

Let's evaluate the given combinations to see which one satisfies this stoichiometry:

1. 4 N₂ and 4 H₂:

   • N₂: 4 → requires \( 4 \times 3 = 12 \) H₂
   • Not enough H₂ (only have 4).

2. 4 N₂ and 4 H₂: (This seems to be a repeat.)

   • Same analysis as previous, not enough H₂.

3. 2 N₂ and 6 H₂:

   • N₂: 2 → requires \( 2 \times 3 = 6 \) H₂
   • Perfect match (uses all).

4. 2 N₂ and 6 H₂: (This is a repeat as well.)

   • Same analysis as previous, perfect match.

5. 8 N₂ and 4 H₂:

   • N₂: 8 → requires \( 8 \times 3 = 24 \) H₂
   • Not enough H₂ (only have 4).

6. 8 N₂ and 4 H₂: (This is a repeat.)

   • Same analysis as previous, not enough H₂.

7. 5 N₂ and 6 H₂:

   • N₂: 5 → requires \( 5 \times 3 = 15 \) H₂
   • Not enough H₂ (only have 6).

8. 5 N₂ and 6 H₂: (Again, a repeat.)

   • Same analysis as previous, not enough H₂.

From the analysis of all options, the combination that produces ammonia with no leftovers is:

2 N₂ and 6 H₂ (Correct option: 2 N₂ and 6 H₂).