Question

It takes 1 molecule of nitrogen and 3 molecules of hydrogen to produce 2 molecules of ammonia using the following formula:1N2+ 3H2 → 2NH3 Identify which combination of molecules will produce ammonia with no leftovers?(1 point)Responses2N2 and 6H22 n sub 2 and 6 h sub 24N2 and 4H24 n sub 2 and 4 h sub 28N2 and 4H28 n sub 2 and 4 h sub 25N2 and 6H2

Answer 1

To produce ammonia (NH3) with no leftovers, we need to follow the stoichiometry of the reaction:

\[ \text{1 N}_2 + \text{3 H}_2 \rightarrow \text{2 NH}_3 \]

From the equation, we see that:

• 1 molecule of nitrogen (N2) reacts with 3 molecules of hydrogen (H2) to produce 2 molecules of ammonia (NH3).

To produce ammonia without leftovers, we need to find combinations of N2 and H2 that follow this ratio. Specifically, for every N2, we need 3 H2 molecules.

Let's analyze the options:

1. 2 N2 and 6 H2:

   • 2 N2 would need \( 2 \times 3 = 6 \) H2.
   • This combination produces \( 2 \times 2 = 4 \) NH3, resulting in no leftovers.

2. 2 N2 and 6 H2: (same as above—this duplicates the previous option).

3. 4 N2 and 4 H2:

   • 4 N2 would need \( 4 \times 3 = 12 \) H2.
   • This combination does not provide enough H2 for the amount of N2.

4. 8 N2 and 4 H2:

   • 8 N2 would need \( 8 \times 3 = 24 \) H2.
   • This combination does not provide enough H2 for the amount of N2.

5. 5 N2 and 6 H2:

   • 5 N2 would need \( 5 \times 3 = 15 \) H2.
   • This combination does not provide enough H2 for the amount of N2.

Thus, the only correct combination that produces ammonia with no leftovers is:

2 N2 and 6 H2.