Your steps are almost correct, but there is a small issue with the calculation in step 2 regarding the subtraction and division. The expression should be clarified to ensure proper order of operations. Here's the corrected solution:
To solve for y in the equation \(3y + x = 33\):
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Subtract \(x\) from both sides of the equation: \[ 3y = 33 - x \]
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Divide both sides by 3 to isolate \(y\): \[ y = \frac{33 - x}{3} \] This can also be written as: \[ y = \frac{33}{3} - \frac{x}{3} = 11 - \frac{x}{3} \]
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Now, substitute \(x = 5\) into the equation: \[ y = \frac{33 - 5}{3} = \frac{28}{3} \approx 9.3333 \]
So your final answer is correct:
Final Answer: When \(x = 5\), the value of \(y\) is approximately \(9.3333\). Thus, the final answer is:
\(y \approx 9.3333\).
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