Question

is this correct?

To solve for y in the equation 3y + x = 33, we need to isolate y. Here are the steps:

1. Subtract x from both sides of the equation: 3y = 33 - x

2. Now, we divide both sides by 3 to solve for y: y = 33 – x / 3

3. Now we substitute x = 5 into the equation: y = 33 – 5 / 3 = 28 / 3 ≈ 9.3333

Final Answer: When x = 5 ,the value of y is approximately 9.3333. Therefore, the final answer is:

y ≈ 9.3333

Answer 1

Your steps are almost correct, but there is a small issue with the calculation in step 2 regarding the subtraction and division. The expression should be clarified to ensure proper order of operations. Here's the corrected solution:

To solve for y in the equation \(3y + x = 33\):

1. Subtract \(x\) from both sides of the equation:
\[
3y = 33 - x
\]

2. Divide both sides by 3 to isolate \(y\):
\[
y = \frac{33 - x}{3}
\]
This can also be written as:
\[
y = \frac{33}{3} - \frac{x}{3} = 11 - \frac{x}{3}
\]

3. Now, substitute \(x = 5\) into the equation:
\[
y = \frac{33 - 5}{3} = \frac{28}{3} \approx 9.3333
\]

So your final answer is correct:

Final Answer: When \(x = 5\), the value of \(y\) is approximately \(9.3333\). Thus, the final answer is:

\(y \approx 9.3333\).