Question
Is this correct?
Solve:
2lnx-2=0
2lnx=2
Lnex=1
E^1=x
Solve:
2lnx-2=0
2lnx=2
Lnex=1
E^1=x
Answers
Steve
yes.
lne is redundant. ln means log_e. SO, things are a bit clearer if you do it
2lnx = 2
lnx = 1
x = e^1 = e
lne is redundant. ln means log_e. SO, things are a bit clearer if you do it
2lnx = 2
lnx = 1
x = e^1 = e
Sora
Thanks! :D