Asked by Sora

Is this correct?
Solve:
2lnx-2=0

2lnx=2
Lnex=1
E^1=x

10 years ago

Answered by Steve

yes.

lne is redundant. ln means log_e. SO, things are a bit clearer if you do it

2lnx = 2
lnx = 1
x = e^1 = e

10 years ago

Answered by Sora

Thanks! :D

10 years ago

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