Asked by Tabisa
solve for x:3x2+2x+6=10(correct to two decimal digits)
Answers
Answered by
PsyDAG
Online "^" indicates an exponent.
Subtract 10 from both sides.
3x^2 + 2x - 4 = 0
Factor.
(3x-2)(x+2)= 0
I hope you can take it from here.
Subtract 10 from both sides.
3x^2 + 2x - 4 = 0
Factor.
(3x-2)(x+2)= 0
I hope you can take it from here.
Answered by
Bosnian
y=a*x^2+b*x+c
3*x^2+2*x+6=10
3*x^2+2*x+6=10
3*x^2+2*x+6-10=0
3*x^2+2*x-4=0
a=3 , b=2 , c=-4
x1=(-b-sqroot(b^2-4*a*c))/(2*a)
x1=(-2-sqroot(2^2-4*3*(-4)/(2*3)
=(-2-sqroot(4+48)/6
=(-2-sqroot(52))/6=
=(-2-sqroot(4*13))/6
=(-2-2*sqroot(13))/6
=(-2/6)*((1+sqroot(13))
=(-1/3)*(1+3.60555)
=(-1/3)*4.6055
=-1.535166
x1=-1.54
x2
x2=(-b+sqroot(b^2-4*a*c))/(2*a)
x2=(-2+sqroot(2^2-4*3*(-4)/(2*3)
=(-2+sqroot(4+48)/6
=(-2+sqroot(52))/6=
=(-2-sqroot(4*13))/6
=(-2+2*sqroot(13))/6
=(-2/6)*(1-sqroot(13))
=(-1/3)*(1-3.60555)
=(-1/3)*(-2.60555)
=0.868516
x2=0.87
3*x^2+2*x+6=10
3*x^2+2*x+6=10
3*x^2+2*x+6-10=0
3*x^2+2*x-4=0
a=3 , b=2 , c=-4
x1=(-b-sqroot(b^2-4*a*c))/(2*a)
x1=(-2-sqroot(2^2-4*3*(-4)/(2*3)
=(-2-sqroot(4+48)/6
=(-2-sqroot(52))/6=
=(-2-sqroot(4*13))/6
=(-2-2*sqroot(13))/6
=(-2/6)*((1+sqroot(13))
=(-1/3)*(1+3.60555)
=(-1/3)*4.6055
=-1.535166
x1=-1.54
x2
x2=(-b+sqroot(b^2-4*a*c))/(2*a)
x2=(-2+sqroot(2^2-4*3*(-4)/(2*3)
=(-2+sqroot(4+48)/6
=(-2+sqroot(52))/6=
=(-2-sqroot(4*13))/6
=(-2+2*sqroot(13))/6
=(-2/6)*(1-sqroot(13))
=(-1/3)*(1-3.60555)
=(-1/3)*(-2.60555)
=0.868516
x2=0.87
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