Question

solve for x:3x2+2x+6=10(correct to two decimal digits)

Answer 1

Online "^" indicates an exponent.

Subtract 10 from both sides.

3x^2 + 2x - 4 = 0

Factor.

(3x-2)(x+2)= 0

I hope you can take it from here.

Answer 2

y=a*x^2+b*x+c

3*x^2+2*x+6=10
3*x^2+2*x+6=10
3*x^2+2*x+6-10=0
3*x^2+2*x-4=0

a=3 , b=2 , c=-4

x1=(-b-sqroot(b^2-4*a*c))/(2*a)

x1=(-2-sqroot(2^2-4*3*(-4)/(2*3)
=(-2-sqroot(4+48)/6
=(-2-sqroot(52))/6=
=(-2-sqroot(4*13))/6
=(-2-2*sqroot(13))/6
=(-2/6)*((1+sqroot(13))
=(-1/3)*(1+3.60555)
=(-1/3)*4.6055
=-1.535166

x1=-1.54

x2
x2=(-b+sqroot(b^2-4*a*c))/(2*a)

x2=(-2+sqroot(2^2-4*3*(-4)/(2*3)
=(-2+sqroot(4+48)/6
=(-2+sqroot(52))/6=
=(-2-sqroot(4*13))/6
=(-2+2*sqroot(13))/6
=(-2/6)*(1-sqroot(13))
=(-1/3)*(1-3.60555)
=(-1/3)*(-2.60555)
=0.868516

x2=0.87