How did you get 103?
2*[(4*SF4)+O=O] - 2*[(4*SF4)+S=O] = ??
I get something in the order of -550 or so.
is answer +103 KJ.. plz chk
Plz explain in detail....
i tried to search on internet but i am confused with co-efficents.. how to set up the equaiton .. plz help me ???
Bond enthalpy is the energy required to break a mole of a certain type of bond.
O=O = 495 kj/mol
S-F = 327 kj/mol
S=O = 523 kj/mol
Use average bond enthalpies to estimate the enthalpy delta H (rxn) of the following reaction:
2SF4 + O2 ---- 2OSF4
Express your answer numerically in kilojoules.
Thanks in Advance
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