Asked by Sarah

Plz explain in detail....

i tried to search on internet but i am confused with co-efficents.. how to set up the equaiton .. plz help me ???



Bond enthalpy is the energy required to break a mole of a certain type of bond.

O=O = 495 kj/mol
S-F = 327 kj/mol
S=O = 523 kj/mol


Use average bond enthalpies to estimate the enthalpy delta H (rxn) of the following reaction:

2SF4 + O2 ---- 2OSF4

Express your answer numerically in kilojoules.

Thanks in Advance

Answers

Answered by DrBob222
SF4 we break 4 SF bonds. That times 2.
O2 we break 1 O2 bond. That times 1.

OSF4. We form 4 S-F bonds and 1 S=O bond. That times 2.
Then BE reactants - BE products = delta H rxn.
Answered by Sarah
can u plz figure out the answer for me .. its very urgent.. thnks ..
i still didn't get it

thnks a lot Dr bob
Answered by DrBob222
Just plug in the numbers and punch your calculator. The idea here is to show you how to do it, not to do it for you.
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