Asked by Sarah
Plz explain in detail....
i tried to search on internet but i am confused with co-efficents.. how to set up the equaiton .. plz help me ???
Bond enthalpy is the energy required to break a mole of a certain type of bond.
O=O = 495 kj/mol
S-F = 327 kj/mol
S=O = 523 kj/mol
Use average bond enthalpies to estimate the enthalpy delta H (rxn) of the following reaction:
2SF4 + O2 ---- 2OSF4
Express your answer numerically in kilojoules.
Thanks in Advance
i tried to search on internet but i am confused with co-efficents.. how to set up the equaiton .. plz help me ???
Bond enthalpy is the energy required to break a mole of a certain type of bond.
O=O = 495 kj/mol
S-F = 327 kj/mol
S=O = 523 kj/mol
Use average bond enthalpies to estimate the enthalpy delta H (rxn) of the following reaction:
2SF4 + O2 ---- 2OSF4
Express your answer numerically in kilojoules.
Thanks in Advance
Answers
Answered by
DrBob222
SF4 we break 4 SF bonds. That times 2.
O2 we break 1 O2 bond. That times 1.
OSF4. We form 4 S-F bonds and 1 S=O bond. That times 2.
Then BE reactants - BE products = delta H rxn.
O2 we break 1 O2 bond. That times 1.
OSF4. We form 4 S-F bonds and 1 S=O bond. That times 2.
Then BE reactants - BE products = delta H rxn.
Answered by
Sarah
can u plz figure out the answer for me .. its very urgent.. thnks ..
i still didn't get it
thnks a lot Dr bob
i still didn't get it
thnks a lot Dr bob
Answered by
DrBob222
Just plug in the numbers and punch your calculator. The idea here is to show you how to do it, not to do it for you.
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