In trapezium ABCD,AB=14cm,AD=10cm,DC=xcm &distance between AB &DC is 8cm. find the value of x & area of the trapezium ABCD

Answer 1

Drop a perpendicular from D to AB, meeting it at P.

Then AP = 6 (Pythagorus)

Since we know nothing about BC, x can be anything from 0 to 8.

The area is (x+14)/2 * 8 = 4(x+14)

If the trapezium is isosceles, then x=2, but without some further knowledge, There's no way to pin down x.