since angle B is a right angle, AB is the height of the trapezoid. So, the area is
(16+40)/2 * √(41^2 - 40^2)
in the given figure ABCD is a trapezium in which AD parallel to BC. Angle ABC= 90degree. AD=16cm, AC=41cm and BC=40cm.find the area of the trapezium.
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Gajaj
252cm
2 answers