Right now, t = 0, the student would be expected to learn
50 - 50e^(-.3*0)
= 50 - 50 or 0 words per hour
when t = 9, they would learn
50 - 50e^(-.3*9)
= 50 - 50/e^2.7
= 46.6 or appr. 47 words/hr
in psychology tests, it is found that students can memorize a list of words after t hours, according to the learning curve y =50 -50e^-0.3t ,where y is the number of words a student can learn during the t^th hour of study. find how many words a student would be expected to learn in ninth hour of study?
3 answers
Abdela
Right now, t = 0, the student would be expected to learn
50 - 50e^(-.3*0)=50-50e^0=50-50=0 when t = 9, they would learn
50 - 50e^(-.3*9)=50-50e^-2.7=50-50(0.0672055127)=50-3.360275637=46.639724363
50 - 50e^(-.3*0)=50-50e^0=50-50=0 when t = 9, they would learn
50 - 50e^(-.3*9)=50-50e^-2.7=50-50(0.0672055127)=50-3.360275637=46.639724363