Dach

This page lists questions and answers that were posted by visitors named Dach.

Questions

The following questions were asked by visitors named Dach.

Answers

The following answers were posted by visitors named Dach.

Right now, t = 0, the student would be expected to learn 50 - 50e^(-.3*0)=50-50e^0=50-50=0 when t = 9, they would learn 50 - 50e^(-.3*9)=50-50e^-2.7=50-50(0.0672055127)=50-3.360275637=46.639724363
2 years ago