In its final trip upstream to its spawning territory, a salmon jumps to the top of a waterfall 1.9m high. What is the minimum vertical velocity neeeded by the salmon to reach the top of the waterfall?

this is the only info I have.

4 answers

I did:
vf^2 = vi^2+2a∆d
0=vi^2+2(9.8)*1.9
vi^2 = = 2(9.8)*1.9
vi=√(37.24)
vi= 6.1m/s
is my answer correct?
works for me
V^2 = Vo^2 + 2g*h = 0,
Vo^2 + (-19.6)1.9 = 0,
Vo^2 - 37.24 = 0
Vo^2 = 36.24
Vo = 6.1 m /s.