In a reaction Mg(s) + 2HCl(aq) → H2(g) + MgCl2(aq), 6.00 g of Mg was present at 0.00 min. After 3.00 min, 4.50 g of Mg remained. Express the average rate as mol of Mg consumed per minute.

Question

I was taught how to use molarity but this question does not tell me molarity, just grams so I do not know how to solve it.

Answer 1

Just convert grams Mg to mols Mg and you have it.
g Mg/min = 1.5/3.0 = 0.5 g Mg/min or 0.5 g/24.3 = approx 0.02 mol Mg/min.

or convert at the beginning but it's more work.
6.00/24.3 = approx 0.25 mols Mg initially.
4.50/24.3 = approx 0.19 mols final.
(delta mols Mg) = approx 0.25-0.19 = about 0.06 mol Mg/3.00 min or about 0.02 mol Mg/min.

Answer 2

Lmao so guys what the answer i need it for my homework 💀

Answer 3

Mrbob222 can you make it clear a little bit cuz 👴🏻👓🤏🏻 GOD DAHYUM. I did not get that😩