as with any rate of change, this would be
(4.50-6.00)/(3.00-0.00) = -1.5/3 = -0.5 g/min
since you said consumed, then that'd be just 0.5 g/min
In a reaction Mg(s) + 2HCl(aq) → H2(g) + MgCl2(aq), 6.00 g of Mg was present at 0.00 min. After 3.00 min, 4.50 g of Mg remained. Express the average rate as gram Mg consumed/min
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