Divide the momentum change by the tuime interval of contact. (Take care to reverse the sign when the velocity direction reverses)
M*(delta V)/t = 1369*[10-(-1.9)]/0.18
= 9.05*10^4 kg m/s
In a particular crash test, an automobile of
mass 1369 kg collides with a wall and bounces
back off the wall. The x components of the initial and final speeds of the automobile are
10 m/s and 1.9 m/s, respectively.
If the collision lasts for 0.18 s, find the
magnitude of the impulse due to the collision.
Answer in units of kg · m/s
1 answer
1 answer