please check for typos. I get 22 total
14 play something
5 basketball alone
9 baseball alone
1 both
that means 15 not 14 play something
I suspect 6 play neither or there are 22 students
In a certain Algebra 2 class of 21 students, 6 of them play basketball and 10 of them play baseball. There are 7 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
3 answers
make a Venn diagram, label the intersection of both circles as x
So x students would play both sports.
It is easy to see that
6-x + x + 10-x + 7 = 21
-x = -2
x = 2
So 2 students play both sports,
prob(picking one of those 2) = 2/21
So x students would play both sports.
It is easy to see that
6-x + x + 10-x + 7 = 21
-x = -2
x = 2
So 2 students play both sports,
prob(picking one of those 2) = 2/21
the answer is 4/21