If you wanted to produce 0.25 L of CO2 gas (at STP), how many grams of sodium bicarbonate would I need to use? Acetic acid is in excess. (IT IS ASSUMED YOUR ANSWER IS IN g NaHCO3 so you do not need to include that in your answer.)

Answer 1

Acetic acid is HC2H3O2 OR CH3COOH or HAc.
NaHCO3 + HAc ==> NaAc + H2O + CO2
mols CO2 gas in 0.25L is 0.25L x (1 mol/22.5L) = approx 0.0112
Using the coefficients in the balanced equation, convert mols CO2 to mols NaHCO3. That's 0.0112 mols CO2 x (1 mol NaHCO3/1 mol CO2) = 0.0112 x 1/1 = 0.0112 mols NaHCO3.
Convert mols NaHCO3 to grams = mols x molar mass.