The reaction: 2C2H2+5O2->5O2->4CO2+2H2O is performed by mixing 175 grams of C2H2 and 175 grams of O2 to produce 127 grams of CO2

Question

1)Limiting reagent
2)Theretical yeield of CO2
3)Percent yield of CO2

Answer 1

change the mass to moles for all three.

Now divide the moles of C2H2, O2, and CO2 by the coefficents 2,5, 4

Which is the lowest number? That is the limiting reageant. WHY?

For yield, how many moles of the limiting reageant so you have. You should get the ratio of coefficents of CO2, and the ratio of the limitng reagent. Convert that to grams.

3. Percent yield. divide the actual yield by the theoritical.