you need to combine the given reactions
... some partial and/or reversed
... to get the desired reaction
2CO2 + H2O --> C2H2 + 5/2 02 ΔH = 1300 kJ
2C + 2O2 --> 2CO2 ΔH = -788 kJ
H2 + 1/2 O2 --> H20 ΔH = -286 kJ
add the 3 reactions, along with the ΔH's
... cancel like terms on opposite sides of the result
At 25°C the following heats of reaction are known:
2C2H2 + 5O2 ---> 4CO2 + 2H2O; ΔH = -2600 kJ
C + O2 ---> CO2 ; ΔH = -394 kJ
2H2 + O2 ---> 2H2O; ΔH = -572 kJ
At the same temperature, calculate ΔH for the following reaction:
2C + H2 ---> C2H2; ΔH = ??
I don't understand how to solve this, what equation would i use?
1 answer