Asked by Kales
Find the change in internal energy for this reaction. Enter in kJ. 2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(l)
Enthalpy of reaction= -2599 kJ
Enthalpy of reaction= -2599 kJ
Answers
Answered by
DrBob222
dE = q + w
You know q.
w is -p(Vfinal-Vinitial)
You have 7 mols gas on the left at 22.4 L/mol if this is at STP. You have only 4 mols gas on the right. That should give you Vfinal and Vinitial and work will be in units of L*atm. Multiply that by 101.325 to convert L*atm to J. Substitute into dE = q + w. Convert J to kJ.
You know q.
w is -p(Vfinal-Vinitial)
You have 7 mols gas on the left at 22.4 L/mol if this is at STP. You have only 4 mols gas on the right. That should give you Vfinal and Vinitial and work will be in units of L*atm. Multiply that by 101.325 to convert L*atm to J. Substitute into dE = q + w. Convert J to kJ.
Answered by
Jay
Correct answer is 394kJ
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