dy/du = sec^2u
du/dv = 1 + 1/v^2
dv/dx = 1/x
dy/dx = dy/du * du/dv * dv/dx
now just crank it out. It's just algebra from here.
If y=tanu, u=v-(1/v), and v=lnx. What is the value of dy/dx at x=e?
3 answers
2/e
oh yeah just solve it