If y=tanu, u=v-(1/v), and v=lnx. What is the value of dy/dx at x=e?

3 answers

dy/du = sec^2u
du/dv = 1 + 1/v^2
dv/dx = 1/x

dy/dx = dy/du * du/dv * dv/dx

now just crank it out. It's just algebra from here.

2/e

oh yeah just solve it

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