If y=tanu, u=v-(1/v), and v=lnx.

tan (u-v)given sin u=3/4 and cos v= -5/13 with U and V in quadrant 2 Use the identity tan (u-v) = (tanu tanv)/[1-tanu tanv) Get
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2. asked by lauren
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4tan^2u-1=tan^2u3tan^2u=1 tan^2u=1/3 sq. root of (tan^2u)=sq. root of (1/3) tanu=sq. root of (3)/3 tanu=sq. root of 1 Did I do
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If y=tanu, u=v-(1/v), and v=lnx. What is the value of dy/dx at x=e?
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2. asked by Sarah
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Given tanu= -1/3 and sinu <0, find sin(u/2)if 0 is less than or equal to u < 2 pie I think its a right triangle in fourth
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2. asked by george
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Verify/prove the following:(sinA+tanA)/(1+secA) = sinA ______________________________ tanu = 1+sinu-cos^2u/cosu(1+sinu)
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2. asked by Kid
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