If (x+1)1/2x and (x-5) are the 1st three term of a linear sequence find their common different.

Answer 1

I will assume your terms are
x+1, 1/2 x, and x-5
for a linear sequence:
(1/2)x - (x+1) = x-5 - (1/2)x
multiply each term by 2
x - 2(x+1) = 2x - 10 - x
x - 2x - 2 = 2x - 10 - x
-2x = -8
x = 4

so the terms are: 5, 2, and -1 which would give a common
difference of -3