Asked by anonymous

If we start with 10 choices, have 5 decisions to make/positions to fill, and repetition isn’t allowed, how many combinations can be made?
Answered by anonymous
252?
Answered by Reiny
yes
Answered by anonymous
and with repetition, it is 2002?
Answered by Reiny
how did you get 2002 ?

You are making decisions and repetition is allowed?
Are you making the same decisions more than once??
Answered by anonymous
it asks this:
How many combinations are possible with 10 initial choices and 5 decisions to make if repetition is allowed?
Answered by anonymous
i used
(r + n – 1)!/r!(n – 1)!
(5 + 10 - 1)!/5!(10 - 1)!
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