If we start with 10 choices, have 5 decisions to make/positions to fill, and repetition isn’t allowed, how many combinations can be made?

Answer 1

252?

Answer 2

yes

Answer 3

and with repetition, it is 2002?

Answer 4

how did you get 2002 ?

You are making decisions and repetition is allowed?
Are you making the same decisions more than once??

Answer 5

it asks this:
How many combinations are possible with 10 initial choices and 5 decisions to make if repetition is allowed?

Answer 6

i used
(r + n – 1)!/r!(n – 1)!
(5 + 10 - 1)!/5!(10 - 1)!