Asked by Anonymous
If we start with 10 choices, have 5 decisions to make/positions to fill, and repetition isn’t allowed, how many combinations can we make?
Answers
Answered by
Reiny
By the definition of combinations that would be "10 choose 5"
= C(10,5) or 10!/(5!5!) = ...
= C(10,5) or 10!/(5!5!) = ...
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