Asked by Christine
If Radium-223 has a half life of 10.33 days, what time duration would it require for the activity associated with this sample to decrease 1.5% of its present value?
Answers
Answered by
oobleck
(1/2)^(x/10.33) = 0.985
x = 0.225 days
Now, if you meant to say "decrease to 1.5%" then that would be
(1/2)^(x/10.33) = 0.015
x = 68.63 days
x = 0.225 days
Now, if you meant to say "decrease to 1.5%" then that would be
(1/2)^(x/10.33) = 0.015
x = 68.63 days
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.