Question
Radium-223 has a half-life of 11.4 days.Approximately how long would it take for the activity of a sample of Radium-223 to decrease to 1.00% of its initial value?
Answers
Devron
(100)*1/2^n=1
Solve for n
1/2^n=1/100
2^n=100
n=ln(100)/ln(2)
n* the number of days (11.4) =should give you the length of time it takes for Radium-223 to decrease to 1.00% of its initial value.
Solve for n
1/2^n=1/100
2^n=100
n=ln(100)/ln(2)
n* the number of days (11.4) =should give you the length of time it takes for Radium-223 to decrease to 1.00% of its initial value.
Michelle
75.7 days