Question
If Radium-223 has a half life of 10.33 days, what time duration would it require for the activity associated with this sample to decrease 1.5% of its present value?
Answers
oobleck
(1/2)^(x/10.33) = 0.985
x = 0.225 days
Now, if you meant to say "decrease to 1.5%" then that would be
(1/2)^(x/10.33) = 0.015
x = 68.63 days
x = 0.225 days
Now, if you meant to say "decrease to 1.5%" then that would be
(1/2)^(x/10.33) = 0.015
x = 68.63 days