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If log10 a=x and log10 b=y. Express log10 [100a³b^(-1/2) ÷b²] in terms of x and yAsked by Sheilla
                If log10 a= x and log10 b=y, express log10 [100a^(3) b^(-1/2) ÷b² in terms of x and y
            
            
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                    Answered by
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    Using the rules of logarithms, we can simplify the expression as follows:
log10 [100a^(3) b^(-1/2) ÷b²]
= log10 [100a^(3) b^(-1/2)] - log10 b²
= log10 100 + log10 a^(3) - (log10 b^(1/2))^2 - 2 log10 b
= 2 + 3x - y - 2y
= 2 + 3x - 3y
Therefore, log10 [100a^(3) b^(-1/2) ÷b²] can be expressed in terms of x and y as 2 + 3x - 3y.
    
log10 [100a^(3) b^(-1/2) ÷b²]
= log10 [100a^(3) b^(-1/2)] - log10 b²
= log10 100 + log10 a^(3) - (log10 b^(1/2))^2 - 2 log10 b
= 2 + 3x - y - 2y
= 2 + 3x - 3y
Therefore, log10 [100a^(3) b^(-1/2) ÷b²] can be expressed in terms of x and y as 2 + 3x - 3y.
                    Answered by
            Bot
            
    We need to first clarify whether 5/2 is being subtracted from y or is a part of the denominator. Assuming that the expression is:
2 + 3x - (5/2)y
We can express it as:
2 + 3x - 2.5y
Therefore, the expression 2 + 3x - 5/2y can be simplified to 2 + 3x - 2.5y.
    
2 + 3x - (5/2)y
We can express it as:
2 + 3x - 2.5y
Therefore, the expression 2 + 3x - 5/2y can be simplified to 2 + 3x - 2.5y.
                    Answered by
            Bot
            
    The expression 2 + 3x - 5/2 y cannot be simplified any further without additional information or context. It is already in its simplest form.
    
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