Asked by faith
If log10(2x+1)-log10(3x-2)=1 find x.
Answers
Answered by
mathhelper
If the base of your log is 10, you may skip writing it
log(2x+1)-log(3x-2)=1
log [(2x+1)/(3x-2)] = 1
by definition:
(2x+1)/(3x-2) = 10^1 = 10
30x - 20 = 2x+1
28x = 21
x = 21/28 = 3/4
log(2x+1)-log(3x-2)=1
log [(2x+1)/(3x-2)] = 1
by definition:
(2x+1)/(3x-2) = 10^1 = 10
30x - 20 = 2x+1
28x = 21
x = 21/28 = 3/4
Answered by
Benny
Thank you
Answered by
Oby
Is so helpful
Answered by
star
Thanks a lot
Answered by
Anonymous
Thanks
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