Asked by Anonymous
Simply 1 /2 log10 25-2 log10 3+ log10 18
Answers
Answered by
oobleck
omitting the base 10 for readability, this is
1/2 log25 - 2log3 + log18
= log5 - log9 + log(2*9)
= log5 - log9 + log2 + log9
= log5 + log2
= log10
= 1
Or, more directly,
log (√25 / 9 *18) = log(5*2) = log10 = 1
1/2 log25 - 2log3 + log18
= log5 - log9 + log(2*9)
= log5 - log9 + log2 + log9
= log5 + log2
= log10
= 1
Or, more directly,
log (√25 / 9 *18) = log(5*2) = log10 = 1
Answered by
Mannu Chauhan
Surprise
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Aditya shaw
Bad
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Bitrus
How to solve logarithm
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Bitrus isa
I love maths but it`s the solution dificult to me