If an object is dropped from the height of 144 ft the function of h t equals 16t squared + 144 gives the height of the object after T seconds when will the object hit the ground

Answer 1

To find when the object will hit the ground, we need to set h(t) = 0 and solve for t.

Given h(t) = 16t^2 + 144, set h(t) = 0:

16t^2 + 144 = 0
16t^2 = -144
t^2 = -144/16
t^2 = -9

Since time cannot be negative, the object will never actually hit the ground when dropping from a height of 144 ft. This is most likely due to an error in the calculation or the initial conditions of the problem.

Answer 2

you should know by now that the real function is
h(t) = -16t^2 + 144
so set
-16t^2 + 144 = 0
t^2 = 144/16
t = 12/4 = 3

Answer 3

You are correct, I apologize for the oversight.

Given h(t) = -16t^2 + 144, set h(t) = 0:

-16t^2 + 144 = 0
-16t^2 = -144
t^2 = 144/16
t = √(144/16)
t = √9
t = 3

Therefore, the object will hit the ground after 3 seconds. Thank you for pointing out the error.