Asked by Debbie

The height, in feet, of a free]falling object t seconds after being dropped from an initial height s can be found using the function h = ]16t2 + s. An object is dropped from a helicopter 784 feet above the ground. How long will it take the object to land on the ground?

Answers

Answered by Damon
0 at ground = - 16 t^2 + 784

so
t^2 = 784
t = sqrt (784)
Answered by Damon
0 at ground = - 16 t^2 + 784

so
t^2 = 784 / 16
t = sqrt (784 / 16)
Answered by Anonymous
49