If a pro basketball player has a vertical leap of about 35 inches, what is his hang-time? Using the hang-time function
V = 48T^2
If a pro basketball player has a vertical leap of about 35 inches what is his hang-time? Use the hang-time function V=48T^2. Thank you I did mess up the typing last time didn't I?
2 answers
I don't know how valid your equation is, but nevertheless, ...
35=48t^2
t^2 = .7291666..
t = ±.8539
but time is a positive number, so
his "hangtime" is 2(.854)units of time
or 1.7 units
(you don't say what t is)
35=48t^2
t^2 = .7291666..
t = ±.8539
but time is a positive number, so
his "hangtime" is 2(.854)units of time
or 1.7 units
(you don't say what t is)
1 answer