A basketball player has a vertical leap of about 36 in. If the equation d=48t^2 describes his hang time t as a function of his vertical leap d. what is his hang time? Show your work.
36=48t^2
t^2=3/4
t=(1/2)sqrt(3)seconds
36=48t^2
t^2=3/4
t=(1/2)sqrt(3)seconds