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can someone help me with this word problem?

if a pro basketball player has a vertical leap of about 20 inches, what is his hangtime?

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It is twice the time that it would take an object to fall 20 inches.

hangtime T = 2 * sqrt(2H/g)

H = 20"/(12 in/ft) = 1.6667 ft
g = 32.2 ft/s^2
T = 0.64 s

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