Here's a basketball problem: A 83.0 kg basketball player is running in the positive direction at 7.5 m/s. She is met head-on by a 101.6 kg player traveling at 5.3 m/s toward her. If the 101.6 kg player is knocked backwards at 3.4 m/s, what is the resulting velocity of the 83.0 kg player?

Answer 1

The speeds of the objects after elastic collision are
v₁= {-2m₂v₂₀ +(m₁-m₂)v₁₀}/(m₁+m₂)
v₂={ 2m₁v₁₀ - (m₂-m₁)v₂₀}/(m₁+m₂)