If a metal wire carries a current of 79

Question

.
0 mA,
how long does it take for 7.90
×
10
20
electrons
to pass a given cross-sectional area anywhere
along the wire? The fundamental charge is
1
.
602
×
10
−
19
C.
Answer in units of s

Answer 1

1 amp=1coulomb/sec=1coulomb/e electrons per second
1amp=1/1.603E-19 electrons/sec

= 6.24E18 electrons per second.

so then 79ma=.079amp=.079*6.24E18 electrons/sec

time=electcrons/rate=7.90E20/.079*6.24E18

time=1603seconds

check all that