North: 5cos40
E: 4 sin40+8
If a man travels 5km,40 degree west of north , then 8km east,find the resultant displacement
4 answers
Both Mrs. Smith and Mrs. Jones had babies the same day in the same hospital. Mrs. Smith took home a baby girl, whom she named Shirley. Mrs. Jones took home a baby girl, whom she named Jane. Mrs. Jones began to suspect, however, that her child had been accidentally switched with the Smith baby in the nursery. Blood tests were made; Mr. Smith was type A, Mrs. Smith was type B, Mr. Jones was type A, Mrs. Jones was type A, Shirley was type O, and Jane was type B. Had a mix-up occurred?
All angles are measured CCW from +x-axis.
Disp. = 5km[130o] + 8km[0o].
X = 5*Cos130 + 8*Cos0 = -3.21 + 8 = 4.78 km.
Y = 5*sin130 + 8*sin0 = 3.83 + 0 = 3.83 km.
Disp. = 4.78 + 3.83i = 6.113 km[38.70].
Disp. = 5km[130o] + 8km[0o].
X = 5*Cos130 + 8*Cos0 = -3.21 + 8 = 4.78 km.
Y = 5*sin130 + 8*sin0 = 3.83 + 0 = 3.83 km.
Disp. = 4.78 + 3.83i = 6.113 km[38.70].
I needed a pitagorus theory