If a man travels 5km 40 degree west of north then 8km east find the resultant displacement

Answer 1

All angles are measured CCW from +x-axis.
Disp. = 5km[130o] + 8km[0o].
X = 5*Cos130 + 8*Cos0 = -3.21 + 8 = 4.79 km.
Y = 5*sin130 + 8*sin0 = 3.83 km.

Disp. = 4.79 + 3.83i = 6.13 km[38.6o].