If a force of 42 newtons is exerted on a 3.0-kilogram bowling ball, what is the resulting acceleration of the ball?(1 point)

Responses

45 m/s2
45 m/s 2

126 m/s2
126 m/s 2

39 m/s2
39 m/s 2

14 m/s2

1 answer

To find the acceleration of the bowling ball, you can use Newton's second law of motion, which states that force equals mass times acceleration (F = ma). You can rearrange this equation to solve for acceleration (a):

\[ a = \frac{F}{m} \]

Where:

  • \( F \) is the force applied (42 newtons),
  • \( m \) is the mass of the object (3.0 kilograms).

Now, plug in the values:

\[ a = \frac{42 , \text{N}}{3.0 , \text{kg}} = 14 , \text{m/s}^2 \]

Therefore, the resulting acceleration of the bowling ball is 14 m/s².