A 5.1 kg bowling ball and a 7.1 kg bowling ball rest on a rack 1.07 m apart.
(a) What is the force of gravity exerted on each of the balls by the other ball?
(b) At what separation is the force of gravity between the balls equal to 2.0 10-9 N?
4 answers
part b says 2.0 E-9
F = G M1 M2 / d^2
= 6.67 * 10^-11 * 5.1 * 7.1 / 1.07^2
= 6.67 * 10^-11 * 5.1 * 7.1 / 1.07^2
part b
2*10^-9 = 6.67*10^-11*5.1*7.1/d^2
solve for d
2*10^-9 = 6.67*10^-11*5.1*7.1/d^2
solve for d
find the force of gravity between two 7.26kg bowling balls separated by 3m