If a force of 42 newtons is exerted on a 3.0-kilogram bowling ball, what is the resulting acceleration of the ball?

1 answer

To find the acceleration of the bowling ball when a force is applied, we can use Newton's second law of motion, which states:

\[ F = m \cdot a \]

Where:

  • \( F \) is the force applied (in newtons),
  • \( m \) is the mass of the object (in kilograms),
  • \( a \) is the acceleration (in meters per second squared).

We can rearrange this equation to solve for acceleration \( a \):

\[ a = \frac{F}{m} \]

Given:

  • \( F = 42 \) newtons,
  • \( m = 3.0 \) kilograms,

We can plug in the values:

\[ a = \frac{42 , \text{N}}{3.0 , \text{kg}} = 14 , \text{m/s}^2 \]

Thus, the resulting acceleration of the bowling ball is \( 14 , \text{m/s}^2 \).