vo= 0
a=5.5m/s^2
v= 28 m/s
t=?
v=vo+at
at=v-vo
t=(v-vo)/a
t=28/5.5
t=5.09 seconds
if a car accelerates from rest at a constant 5.5 m/s^2, how long will it take for the car to reach a velocity of 28 m/s
3 answers
Vi= 0
Vf= 28 m/s
a=5.5 m/s²
t=?
Vf=Vi+at
t=Vf+Vi/a
(Since Vi is 0 it can be crossed out)
=28 m/s/5.5 m/s²
=5.09 (m/s/m/s²)
=5.09 m/s
Vf= 28 m/s
a=5.5 m/s²
t=?
Vf=Vi+at
t=Vf+Vi/a
(Since Vi is 0 it can be crossed out)
=28 m/s/5.5 m/s²
=5.09 (m/s/m/s²)
=5.09 m/s
IJOLE, 10 YEARS AGO
3 answers