Car A is 12 m ahead of car B on a straight stretch of road. Car A starts from rest and accelerates away from B at 4.0 m/s2. Two seconds later B starts from rest and accelerates after A at 6.0 m/s2. How long will it take B to catch A? How far will B have travelled?

Question

Car A is 12 m ahead of car B on a straight stretch of road.  Car A starts from rest and accelerates away from B at 4.0 m/s2.  Two seconds later B starts from rest and accelerates after A at 6.0 m/s2.  How long will it take B to catch A?  How far will B have travelled?

bobpursley · Answer

B travels distanceA + 12 B=1/2 6 *(t-2)^2 A-1/2 4 *t^2 B+12=A put A, B in that, solve for t B's time is t-2 How far, solve for B

Amirreza · Answer

Are u dumb? How is B+12 = A? if A is 12 m AHEAD of B, then how tf A go LONGER THAN B?

Amirreza · Answer

So Ur saying that A-12 = B, which means that A must go a longer distance than B to get a positive number. YET IF A IS AHEAD, THAT MEANS IT WENT A SHORTER DISTANCE THAN B. Stop posting the wrong answer for people to fail their physics tests