A train starts from rest and then accelerates at a constant acceleration of 1.4ms-2 for 10s. The train then moves with a constant velocity for a further 20s before the brakes are applied bringing the train to a stop with a constant deacceleration of 2.8ms-2 Calculate the total distance covered by the train.
Please explain and help
3 answers
Graph velocity vs time. That area below the graph is the distance covered. You can easily determine the area from basic geometry.
V1 = a*t = 1.4 * 10 = 14 m/s.
d1 = V1*t = 14 * 20 = 280 m.
V2^2 = V1^2 + 2a*d2 = 0.
14^2 - 5.6d2 = 0
d2 = 35 m.
d = d1+d2 = 280 + 35 = 315 m. = Total distance.
d1 = V1*t = 14 * 20 = 280 m.
V2^2 = V1^2 + 2a*d2 = 0.
14^2 - 5.6d2 = 0
d2 = 35 m.
d = d1+d2 = 280 + 35 = 315 m. = Total distance.
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